https://leetcode-cn.com/problems/best-time-to-buy-and-sell-stock-ii/ 
解法1:贪心
与121题不同,这题可以多次买卖没有对交易次数限制,所以我们可以采用贪心策略,只要赚钱,我们就将股票出售
buyday记录购买日期,i遍历数组,若第i天大于buyday时的价格就让结果值加上这个利润,且更新buyday=i
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 | class Solution {public:
 int maxProfit(vector<int>& prices) {
 int buyday=0;
 int res=0;
 int n=prices.size();
 for(int i=0;i<n;i++)
 {
 if(prices[i]<prices[buyday])
 buyday=i;
 else if(prices[i]>prices[buyday])
 {
 res+=prices[i]-prices[buyday];
 buyday=i;
 }
 }
 return res;
 }
 };
 
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